Chemistry

Redox Equation Balancer

Balance redox equations in acidic or basic medium with atom and charge conservation (H₂O / H⁺ / OH⁻).

Redox / half-reaction balancer

Acidic or basic medium · atom + charge balance

Write charges as Fe2+, MnO4-, or SO4^2-. Do not include free e⁻ — the solver adds H₂O / H⁺ (acidic) or converts to OH⁻ (basic).

Balanced (acidic)

MnO4⁻ + 5Fe^{2+} + 8H⁺ → Mn^{2+} + 5Fe^{3+} + 4H₂O

Charge check: 17 = 17

  1. Parse ions and charges from the skeleton equation.
  2. Enforce atom conservation for every element and overall charge conservation.
  3. Add H₂O / H⁺ as needed (acidic half-reaction style auxiliaries).
  4. Scale to the smallest positive integer coefficients.
  5. Balanced (acidic): MnO4⁻ + 5Fe^{2+} + 8H⁺ → Mn^{2+} + 5Fe^{3+} + 4H₂O
ElementReactantsProducts
Fe55
H88
Mn11
O44

What is the Redox Equation Balancer?

Redox reactions transfer electrons between species: oxidation loses electrons, reduction gains them. Many aqueous redox equations cannot be balanced by inspection alone because oxygen, hydrogen, and charge must be adjusted together with the principal atoms. The half-reaction method (ion–electron method) separates oxidation and reduction, balances atoms and charge in each half, then combines them so electrons cancel.

In acidic medium, oxygen is balanced with H₂O and hydrogen with H⁺. In basic medium, the same acidic skeleton is converted by adding OH⁻ to neutralize H⁺, producing water on one side and leaving net OH⁻ where needed. Both atom counts and net charge must match on the reactant and product sides of the final equation.

The Redox Equation Balancer on Online Science Tools accepts ionic or molecular skeletons such as MnO4- + Fe2+ = Mn2+ + Fe3+, chooses acidic or basic medium, and returns the smallest whole-number equation with step notes and an atom/charge check. Use it to verify homework half-reaction work, then carry coefficients into the Reaction Stoichiometry Calculator when yields matter.

  • Split into oxidation and reduction half-reactions when needed
  • Acidic: balance O with H₂O, H with H⁺, then charge with e⁻
  • Basic: convert H⁺ by adding equal OH⁻ (H⁺ + OH⁻ → H₂O)
  • Electrons lost must equal electrons gained before adding halves

Mathematical / chemical formulas

Conservation constraints for a redox equation in aqueous solution:

For every element X:
  Σ atoms(X)_reactants = Σ atoms(X)_products

Charge:
  Σ (coeff × charge)_reactants = Σ (coeff × charge)_products

Acidic half-reaction pattern (example MnO₄⁻ → Mn²⁺):
  MnO₄⁻ → Mn²⁺
  MnO₄⁻ → Mn²⁺ + 4H₂O
  MnO₄⁻ + 8H⁺ → Mn²⁺ + 4H₂O
  MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
  • Write ion charges as Fe2+, MnO4-, or with carets (SO4^2-).
  • Spectator ions may be omitted in net ionic redox equations.
  • If the skeleton already includes H₂O / H⁺ / OH⁻, the balancer may still adjust them.

Step-by-step example: Permanganate oxidizing Fe²⁺ (acidic)

Balance MnO₄⁻ + Fe²⁺ → Mn²⁺ + Fe³⁺ in acidic aqueous solution.

  1. Reduction: MnO₄⁻ → Mn²⁺; add 4 H₂O, then 8 H⁺, then 5 e⁻.
  2. Oxidation: Fe²⁺ → Fe³⁺ + e⁻.
  3. Multiply the iron half by 5 so electrons cancel (5e⁻).
  4. Add: MnO₄⁻ + 5Fe²⁺ + 8H⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O.
  5. Check: Mn, Fe, O, H atoms and net charge (+17) match on both sides.

Enter MnO4- + Fe2+ = Mn2+ + Fe3+, choose Acidic, and confirm the same coefficients in the Redox Equation Balancer.

Frequently asked questions

Is this a half reaction calculator for acidic and basic media?

Yes. Choose acidic or basic medium. The tool balances atoms and charge, adding H₂O, H⁺, or OH⁻ as required, and shows steps plus an atom inventory so you can compare with hand-worked half-reactions.

How do I enter ion charges?

Append the charge after the formula: Fe2+, Zn2+, MnO4-, or use a caret for polyatomic ions such as Cr2O7^2- and SO4^2-. Neutral species like Zn, H2, and MnO2 need no charge suffix.

When should I use basic medium?

Use basic when the reaction occurs in alkaline solution or the expected products include OH⁻ (for example permanganate to MnO₂ with sulfite in base). Switching medium changes how H⁺/OH⁻/H₂O appear in the final equation.

How is this different from the Chemistry Equation Balancer?

The general balancer conserves atoms for molecular equations. The redox balancer also conserves charge and can introduce solvent-derived H₂O, H⁺, and OH⁻ that were not in your skeleton—essential for aqueous half-reaction problems.

Keep learning with more calculators and study guides on Online Science Tools.

Practice problems & worked examples

Practice alongside the redox balancing above. Each problem includes a full worked solution so you can check your reasoning step by step.

Practice problem 1

Permanganate + Fe²⁺ (acidic)

Balance in acid: MnO₄⁻ + Fe²⁺ → Mn²⁺ + Fe³⁺.

Show solution

Worked solution

  1. Mn half: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O.
  2. Fe half: Fe²⁺ → Fe³⁺ + e⁻; multiply by 5.
  3. Add and cancel electrons.

Answer: MnO₄⁻ + 5Fe²⁺ + 8H⁺ → Mn²⁺ + 5Fe³⁺ + 4H₂O

Practice problem 2

Zinc dissolving in acid

Balance: Zn + H⁺ → Zn²⁺ + H₂.

Show solution

Worked solution

  1. Oxidation: Zn → Zn²⁺ + 2e⁻.
  2. Reduction: 2H⁺ + 2e⁻ → H₂.
  3. Combine: Zn + 2H⁺ → Zn²⁺ + H₂.

Answer: Zn + 2H⁺ → Zn²⁺ + H₂

Practice problem 3

Dichromate + Fe²⁺

Balance in acid: Cr₂O₇²⁻ + Fe²⁺ → Cr³⁺ + Fe³⁺.

Show solution

Worked solution

  1. Cr half needs 14 H⁺ and 6 e⁻, producing 2 Cr³⁺ + 7 H₂O.
  2. Six Fe²⁺ supply six electrons.

Answer: Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ → 2Cr³⁺ + 6Fe³⁺ + 7H₂O

Practice problem 4

Basic permanganate + sulfite

Balance in base: MnO₄⁻ + SO₃²⁻ → MnO₂ + SO₄²⁻.

Show solution

Worked solution

  1. Balance as if acidic, then neutralize H⁺ with OH⁻.
  2. Net water and OH⁻ remain on opposite sides.

Answer: 2MnO₄⁻ + 3SO₃²⁻ + H₂O → 2MnO₂ + 3SO₄²⁻ + 2OH⁻

Practice problem 5

Charge check

Why must net charge match on both sides of a balanced ionic redox equation?

Show solution

Worked solution

  1. Electrons are conserved when half-reactions are combined.
  2. Charge conservation is required along with atom conservation.

Answer: Atom and charge conservation (electrons cancel between halves)

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